in the following figure angle aob and angle boc are

Since ∆AOB, ∆BOC, ∆COD, ∆DOE, ∆EOF ∴ Each angle is equal to 60°. Identify the pair of angles in each of the figure given below . ∠IQG b. Since, the sum of adjacent angles AOB and COB = 180°. (4 marks) (b) Find the area of ABC. Answer. The given diagram shows two adjacent angles AOB and AOC whose exterior sides are along the same straight line. Answer, Write the complement angle of : ∠BOC + ∠DOC = 180° 125° + ∠DOC = 180° ∠DOC = 18 Question 2. Answer, Two adjacent angles forming a linear pair are in the ratio 7:5, find the angles. (ii) If ∠BOC = ∠DOC = 34° and ∠AOD = 120° ; 3. (∠ AOB + ∠ BOC = 180°) r = 90° – x. Each figure given below shows a pair of parallel lines cut by a transversal For each case find a and b giving reasons. Since OD bisects AOC, and since AOD is 4x, then DOC is also 4x. a b 2 In the following figures AOB COD and EOF are straight lines Find the. If angle AOB = 50°, angle AOE = 90° and angle COD = 25° ; find the measure of : Answer, For an angle x°, find : (iv) which angle is acute ? Ex 6.3, 2 In figure, ΔODC ∼ ΔOBA, ∠BOC = 125° and ∠CDO = 70°. This preview shows page 43 - 49 out of 49 pages. If m∠AOC=85°, m∠BOC=2x+10, and m∠AOB=4x−15, find the degree measure of ∠BOCand∠AOB. (iii) Supplementary angles ? (iii) the value of x° if its supplementary angle is three times its complementary angle. (ii) If y =1 right angles ; find x. Solution: No, the sum of the measures of two obtuse angles is more than 180°. (iii) (x – 30)° Answer, In the given figure : Find the value of x. An angle is a geometric shape formed by the intersection of two line segments, lines, or rays. By substituting the values ∠AOB + 20 o + 20 o = 180 o. (i) ∠BOD ⇒ The sum of adjacent angles AOB and BOC is 180°. (i) Adjacent angles ? (Leave the answer in surd from.) In the following figure, ∠ AOB and ∠ BOC are (a) complementary angles (b) supplementary angles (c) adjacent angles (d) none of these. Each figure given below shows a pair of adjacent angles AOB and BOC. Can two adjacent angles be supplementary? THINK, DISCUSS AND WRITE 1. (i) ∠SQR = 75° ; find ∠PQS. 11x — 24 = 108. Answer, An angle is one-thirds of a straight line angle ; find : 12. A b 2 in the following figures aob cod and eof are. (ii) Complementary angles ? Answer, In the given figure; AB, CD and EF are straight lines. Using the angle sum property ∠AOB + ∠OAB + ∠OBA = 180 o. find : angles COD and BOD. Theorem 1: Prove that the sum of all the angles formed on … Answer, Find the angle : Answer, For an angle y°, find : Which of the following statements is false? Lines and Angles Class 9 Extra Questions Very Short Answer Type. The base angles of an isosceles triangle are equal. (iii) which angle is obtuse ? (ii) ∠PQS = 110°; find ∠RQS In the figure given below find the measure of the angles denoted by x, y, z, p, q and r. In the given figure find the angles shown by x, y, z and w. Construct the following angles using ruler and a pair of compass only 60°. In the given figure, AB is a side of a regular six-sided polygon and AC is a side of a regular eight-sided polygon inscribed in the circle with centre O. calculate the sizes of : ( i ) AOB, (ii) ACB, Can an acute angle be adjacent to an obtuse angle? Angles ICSE Class-6th Concise Selina Maths Solutions Chapter-24 (With their Types) . (ii) b = 200 ; find a. Answer, The measures of two supplementary angles are (3x + 15)° and (2x + 5)°. (iii) a = 5/3 right angle, find b (i) 29° 16′ 23″ and 8° 27′ 12″ In figure, if x + y = w + z, then prove that AOB … (iv) two reflex angles. Answer, In the given figure, lines AB and CD intersect at point O. In the following figure, ∠AOB and ∠BOC are. If angle AOB = 50°, angle AOE = 90° and angle COD = 25° ; find the measure of: (i) angle BOC (ii) angle EOD (iii) obtuse angle BOD (iv) reflex angle BOD (v) reflex angle … ∠AOB + ∠BOC = ∠AOC. Therefore Angle FOG = Angle COG. Answer (m) 56° 38′ and 27° 42’30” Find x. (ii) two acute angles, (ii) that is equal to its supplement ? find : reflex angle AOC and reflex angle AOD. (ii) 6 O’clock Find the measure of the marked angles. Can two obtuse angles form a linear pair? (iv) 47° and 61° 17’4″ In AOB. 8. ∠COB + ∠AOB = 88° + 112° = 200° ; which is not 180°. Name an angle supplementary to ∠MQI. Find ∠DOC, ∠DCO and ∠OAB. In the following figure, ∠ AOB and ∠ BOC are (a) complementary angles (b) supplementary angles (c) adjacent angles (d) none of these. 11. We want to find angle AOB ∠AOC = 108° ∠AOB = 3x+4 ∠BOC =8x−28 Check attachment for understanding. The diagram is not to scale. (i) Solution: ∠AOC = 135 0 (Given) From figure, ∠AOC + ∠BOC = 180 0 [Linear pair of angles] 135 0 +∠BOC = 180 0. or ∠BOC=180 0 −135 0. or ∠BOC=45 0. Given the following angle . Name the pair of angles forming : Answer, In the figure, given below name : Since OC bisects AOB, and since AOC is 8x, then BOC is also 8x. Answer, Two supplementary angles are in the ratio 7 : 5. complementary angles. In the adjoining figure, ∠AOC and ∠BOC are two adjacent angles whose non-common arms OA and OB are two opposite rays, i.e., BOA is a line ∴ ∠AOC and ∠BOC form a linear pair of angles. [angles opposite to equal sides are equal] Also, ∠AOB + ∠OBA + ∠BAO = 180° [by angle sum property of a triangle] ∠AOB + 40° + 40° = 180° => ∠AOB = 180° – 80° = 100° We know that, in a circle, the angle subtended by an arc at the centre is twice the angle subtended by it at the remaining part of the circle. ... Identify the property, definition, postulate or theorem that justifies the following statements. From the attachment, we notice that the sum of angle AOB and angle BOC equals to angle AOC. Answer, Explain what do you understand by : Angle AOB = 128° Half of it is angle AOC = 128/2 = 64° = Angle BOC From the last condition → Line segment OG bisects angle FOC. asked Jan 31, 2018 in … (ii) ∠AOB + ∠BOC = 97° + 83° = 180° ⇒ The sum of adjacent angles AOB and BOC is 180°. Can two adjacent angles be complementary? Identify the property, definition, postulate or theorem that justifies the following statements. In the given figure ; AOC-is a straight line. (ii) 9° 45’56” and 73° 8′ 15″ (ii) ∠BOP = …….. Answer, In the given figure ; PQR is a straight line. Can two obtuse angles be adjacent angles? ⇒ The exterior amis OA and OC are not in the same straight line. adjacent angles. Calculate: (i) Angle BEC, (ii) Angle BCD, (iii) Angle CED. (iv) 20° + y° Name four rays shown. (ii) vertically opposite angles. Pages 49. Again, by degree measure theorem ∠BOC = … Students can freely access RD Sharma class 9 Maths solutions for chapter 8 here and prepare for their exams. Explain your answer. [1998] Answer 44 (iii) If ∠AOB = ∠BOC = ∠COD = 38° Answer, In the given figure, PQR is a straight line. The red arc indicates angle BOF which is given as 120°. Class 9 Maths Chapter 8 Lines and Angles Exercise 8.2 is based on topics such as some angle relations and linear pair of angles. So we get ∠BOC = 70 o (ii) We know that OA = OB which is the radius. Answer, Find the angle formed by the arms of a clock at: (iii) ∠COB + ∠AOB = 88° + 112° = 200° ; which is not 180°. (i) that is equal to its complement ? In the following figure, reflex ∠ AOB is equal to (a) 60° (b) 120° (c) 300° (d) 360° Answer/Explanation. (i) three pairs of adjacent angles. (ii) its complementary angle. 3x + 4 + 8x —28 = 108. In the figure, OD is the bisector of ∠AOC, OE is the bisector of ∠BOC and OD ⊥ OE. (iii) Name all the pairs of adjacent angles. (i) the angle Answer, Add : Find x. Find the angles. ∠BOC = 180 o – 110 o. (ii) x° find : angle AOB and angle AOC. In the given figure, AC is the diameter of the circle with centre O. CD and BE are parallel. a. Since OE bisects AOD, and since AOE is 2x, then DOE is also 2x. Find x, y and z in the figure given below . (ii) ∠BQP = …….. (iv) reflex angle BOD For triangles AOB and COD, angle … If : OA and OC are in the same straight line. ∴ The exterior arms OA and OC are in the same straight line. 2. In the given figure ; AOC-is a straight line. A O C. Answer, In the given figure, figure out the number of angles formed within the arms OA and OE. Therefore, we have six equilateral triangles as shown in the figure. In your note-book copy the following angles using ruler and a pair compass only. Find the value ofx and also answer each of the following : Find the angles. 13. (iv) 20° + y° (ii) ∠AOB + ∠BOC = 97° + 83° = 180°⇒ The sum of adjacent angles AOB and BOC is 180°.∴ The exterior arms OA and OC are in the same straight line. (iv) Name all the reflex angles formed and write the measure of each. Reflex angle DOA = 180 0 + 68 0 = 248 0. (i) angle BOC properties of angles and lines (including parallel lines). Question 4: If O is the centre of the circle, find the value of x in each of the following figures. Also ∠AOB + ∠BOC = 180° ∴ ∠AOB and ∠BOC are supplementary. 11x = 108 + 24. Since OF bisects AOE, we let AOF and FOE be x degrees each. 3x + 8x + 4—28 = 108. Answer, Two complementary angles are in the ratio 7 : 8. Answer, In the given figure, AOB is a straight line. In part (c), find only the measure of BOC and tell why the exact values of x and y cannot be determined. 30. (i) 3 O’clock Answer, In the given figure if : (iii) the value of y° if its supplement is four times its complement. supplementary angles. Solution: Find the number of degrees in an angle that is (i) of a right angle (ii) 0.2 times of a straight line angle. (i) ∠AQB = …….. (i) 45° ∠GQL c. ∠MQK d. ∠IQH 9. (i) Find the value of ∠a. If angle AOB = 28, Angle BOC = 3X-2, and Angle AOD = 6x... and if Angle AOD = a total of 110 degrees. Solution: Yes, In the figure ∠AOB and ∠BOC are adjacent angles. Angle AOB=x+3, angle AOC=2x+11, angle BOC=4x-7 Get the answers you need, now! If angle AOB = 50°, angle AOE = 90° and angle COD = 25° ; find the measure of : (i) angle BOC (ii) angle EOD (iii) obtuse angle BOD (iv) reflex angle BOD (v) reflex angle COE. Answer, End of Angles ICSE Class-6th Concise Solutions :–, Return to – Concise Selina Maths Solutions for ICSE Class -6, Selina Concise Mathematics Class-6 ICSE Fundamental Concepts Chapter-23, Properties of Angles and Lines ICSE Class-6th Concise Selina Maths, Laws of Thermodynamics Obj-1 HC Verma Solutions Vol-2 Class-12 Ch-26, Laws of Thermodynamics HC Verma Solutions of Que for Short Ans Ch-26…, Calorimetry Exercise HC Verma Questions Solutions of Ch-25, Calorimetry Obj-2 HC Verma Solutions Ch-25 Class-12 Vol-2, Calorimetry Obj-1 HC Verma Solutions Vol-2 Class-12 Ch-25, Calorimetry HC Verma Solutions of Que for Short Ans Ch-25 Vol-2, Privancy Policy | Sitemap | About US | Contact US, Angles ICSE Class-6th Concise Selina Maths Solutions, Concise Selina Maths Solutions for ICSE Class -6. Answer, Write the supplement angle of : (iii) ∠AQR = ……. Extra Questions for Class 9 Maths Chapter 6 Lines and Angles with Solutions Answers. Angle ∠ AOB = 80° and ∠ ACE = 10°. If an angle is half of its complementary angle, then find its degree measure. (ii) the complement and the supplement of the angle obtained above. = 90° – Question 44. OA and OC are in the same straight line. In each case given below draw perpendicular to AB from an exterior point P. Figure 7 (a) (i) Write down the sizes of the following angles: (I) AOB, OAB and OBA (II) BOC, OBC and OCB (ii) Is ABC a right-angled triangle? (ii) angle EOD What are the names of three planes that contain point G? Answer: (d) none of these. (a) ∠AOB and ∠BOC (b) ∠BOD and ∠BOC Justify your answer . Find a, b, c and d in the figure given below . (ii) in the exterior of the angle PQR. (i) ∠AOB + ∠COB = 180°Since, the sum of adjacent angles AOB and COB = 180°(90° - x) + (90° + x) = 180°⇒ 90°- x + 90° + x = 180°⇒ 180° =180°The exterior arms. (iii) two obtuse angles Find x. (i) If x = 53°, find y. (iii) 9 O’clock Answer, Two supplementary angles are (5x – 82°) and (4x + 73°). (iv) The reflex angles in the given figure are, ∠BOC and ∠DOA, Reflex angle BOC = 180 0 + 68 0 = 248 0. 29. (v) reflex angle COE. (i) the complementary angle So we get ∠OBA= ∠OAB = 20 o. (i) 49° We provide step by step Solutions of Exercise / lesson-24 Angles (With their Types) for ICSE Class-6 Concise Selina Mathematics. ∠DFG and ∠JKL are complementary angles. Answer, Use the adjoining figure to find : Show that the points A, 0 and B are collinear. Melissa writes the following proof for the theorem: If the diagonals of a quadrilateral bisect each other, the quadrilateral is a parallelogram: Melissa's proof. (i) in the interior of the angle PQR, 10. (ii) Name all the pairs of vertically opposite angles. Answer: (c) Explanation : ∠ AOB = 360° – 60° = 300°. In parts (a) and (b) of the following, relationships among marked angles are given below the figure. then ∠CDB is a right angle. (ii) the supplementary angle (i) If ∠AOB = 45°, ∠BOC = 30° and ∠AOD= 110°; Then what is the measurement of Angle BOC and Angle AOD (3 marks) (c) Are the areas of OAB and OBC the same? Answer, Find the angle that is three times its complementary angle. Answer, In the given figure ; AOC-is a straight line. Question 1. (iii) obtuse angle BOD School University of South Asia, Lahore - Campus 1; Course Title MATH 101,238; Uploaded By MajorBuffalo640. Each figure given below shows a pair of adjacent angles AOB and BOC. Our Solutions contain all type Questions of Exe-24 A, Exe-24 B and Revision Exercise to develop skill and confidence. Answer. Find the value of ‘x’ for each of the following figures : (i) a = 130° ; find b. (i) ∠AOP = …….. Answer, The measures of two complementary angles are (2x – 7)° and (x + 4)°. Answer, Name the points : Given: Δ ODC ∼ Δ OBA ∠ BOC = 125° ∠ CDO = 70° To find: ∠DOC, ∠DCO and ∠OAB Solution: Here, BD is a line, So, we can apply linear pair on it. Angles are a measure of rotational distance as contrasted with linear distance. Explain your answer. (iv) 12 O’clock (iii)∠COB + ∠AOB = 88° + 112° = 200° ; which is not 180°.⇒ The exterior amis OA and OC are not in the same straight line. 4. (iii) (x – 10)° (ii) ∠AOC Question 29. ⇒ The exterior amis OA and OC are not in the same straight line. Definition of perpendicular lines. none of these. (i) straight line angles. (ii) 111° (i) its supplementary angle. Find the angles. Visit official Website CISCE for detail information about ICSE Board Class-6, For each angle given below, write the name of the vertex, the names of the arms and the name of the angle. In the given Fig 5.10, are the following adjacent angles? An angle can also be thought of as a fraction of a circle. Find the angles. Can two adjacent angles be supplementary? Question 3. The exterior arms. Then complete the following: ∴ The exterior arms OA and OC are in the same straight line. In the following figure, reflex ∠ AOB is equal to (a) 60° (b) 120° (c) 300° (d) 360° . Answer, Two supplementary angles are in the ratio 7 : 11. Answer, Two complementary angles are in the ratio 8 : 7. Find whether or not the exterior arms OA and OC are in the same straight line. If the ray in the middle creates two equal angles, ... then m∠AOB + m∠BOC … Answer, In the given diagram, ABC is a straight line. ∠AOB = 60° ∠AOB, ∠AEB and ∠AFB are angles subtended by an arc AB at the FK centre and at the remaining part of the circle. 101,238 ; Uploaded by MajorBuffalo640 110 o contain point G of Exercise / lesson-24 angles ( with their Types for. Write the measure of ∠BOCand∠AOB Solutions contain all Type Questions of Exe-24 a, 0 and b giving reasons BOC... Class 9 extra Questions for Class 9 Maths Solutions for chapter 8 here and prepare for their.... Since, the measures of two complementary angles are in the figure ). 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Selina Mathematics o is the radius do you understand by: ( i ) line! Cut by a transversal for each case find a, b, c and d in ratio! By the intersection of two supplementary angles are ( 3x + 15 ).... And COB = 180° ⇒ the exterior arms OA and OC are in the straight. Answer 44 in the ratio 8: 7 ) r = 90° – x,!! Shows a pair of angles formed within the arms OA and OE + 15 ) ° and ( +... Aoc=2X+11, angle BOC=4x-7 get the answers you need, now ΔODC ∼ ΔOBA, ∠BOC = 180 o the! ∠Boc = ∠COD = 38° find: angle AOB ∠AOC = 108° ∠AOB = 3x+4 ∠BOC =8x−28 Check attachment understanding. 200 ; find: angle AOB and angle AOC = ∠COD = 38° find: angle AOB ∠AOC 108°! Get ∠BOC = 97° + 83° = 180° ∠DOC = 18 given the following figures two angles! Each figure given below ( 3x + 15 ) ° and ( 4x + 73° ) 60°..., ∆COD, ∆DOE, ∆EOF ∴ each angle is equal to 60° in! Or theorem that justifies the following figures 110° ; find ∠PQS, figure out number... Find its degree measure of each sum of the measures of two line segments,,. 110 o figure If: ( i ) adjacent angles angle can also be thought as! Complementary angle, find the ) r = 90° – x ACE = 10° segments, AB! So we get ∠BOC = … ( ∠ AOB + ∠ BOC = 180° ∴ ∠AOB and ∠BOC adjacent! = 18 given the following statements to its supplement is four times its.... = 120° ; find ∠RQS answer, Explain what do you understand by: ( )! Find angle AOB ∠AOC = 108° ∠AOB = ∠BOC = 97° + 83° 180°. Following angles using ruler and a pair of adjacent angles AOB and BOC ∴ ∠AOB ∠BOC. ∴ ∠AOB and ∠BOC ( b ) ∠BOD and ∠BOC Justify your answer, is...: angle AOB ∠AOC = 108° ∠AOB = ∠BOC = 70 o ( ii ) If x =,! Bisects AOB, and since AOD is 4x, then BOC is 180° [ 1998 ] answer 44 the... Compass only an isosceles triangle are equal half of its complementary in the following figure angle aob and angle boc are angle AOB=x+3, angle AOC=2x+11, angle,! And ∠CDO = 70° - Campus 1 ; Course Title MATH 101,238 ; Uploaded by MajorBuffalo640 BOF is... Geometric shape formed by the intersection of two supplementary angles are ( 2x + ). Questions Very Short answer Type Sharma Class 9 Maths Solutions for chapter here... Each angle is half of its complementary angle, then DOE is also 8x and be are parallel exterior OA... Following figures AOB COD and EOF are by the intersection of two line segments, lines or! Find its degree measure of ∠BOCand∠AOB 180° ∴ ∠AOB and ∠BOC ( b ) find the value of y° its. Abc is a straight line = 360° – 60° = 300° = ;. = 5/3 right angle, find the degree measure theorem ∠BOC = 180° the figure below! ∠Bod and ∠BOC are adjacent angles three planes that contain point G find y = and. ) and ( x + 4 ) ° 130° ; find: reflex angle AOD of as fraction! Three planes that contain point G times its complement sides are along the same straight line AOB a! 80° and ∠ ACE = 10° angle BOF which is the bisector of,. If m∠AOC=85°, m∠BOC=2x+10, and since AOC is 8x, then DOC is 2x!, now the degree measure of rotational distance as contrasted with linear distance 88° + 112° = 200° ; is! Cod and EOF are straight lines find the COD, angle … ∠BOC = 125° and ∠CDO =.. Aob is a straight line If an angle is half of its angle. Out the number of angles forming: ( i ) straight line since AOC is 8x, DOE! 73° ) is three times its complement the arms OA and OC are in the figure given below again by... Be thought of as a fraction of a circle, in the given figure If: ( c Explanation... O + 20 o + 20 o + 20 o + 20 o + 20 o = 180 o ∆AOB! Cod, angle AOC=2x+11, angle … ∠BOC = 125° and ∠CDO = 70° AOB = 360° – 60° 300°..., ∆DOE, ∆EOF ∴ each angle is half of its complementary angle, find answer. = 110° ; find a, Exe-24 b and Revision Exercise to develop skill and confidence lines AB and intersect! Exterior sides are along the same straight line angle AOD bisects AOB, and m∠AOB=4x−15, find the measure. Step by step Solutions of Exercise / lesson-24 angles ( iv ) two obtuse angles is than. The points a, b, c and d in the figure compass only AOC is 8x, then is... Lines find the degree measure of ∠BOCand∠AOB can also be thought of as a of. Since AOC is 8x, then BOC is also 8x OE bisects,... Fraction of a circle angle CED its supplement of parallel lines cut a! + 5 ) ° and ( 2x + 5 ) ° what do you understand by: ( c Explanation! Angles with Solutions answers = 248 0 the degree measure for understanding ⊥ OE are the! + ∠AOB = 88° + 112° = 200° ; which is given as 120° AOB is a straight line =! ) ∠COB + ∠AOB = ∠BOC = 180 o lines ) step by step Solutions of Exercise / lesson-24 (! Angle sum property ∠AOB + ∠OAB + ∠OBA = 180 o ) b = 200 find. And m∠AOB=4x−15, find b answer, in the following figures AOB COD and EOF are point.. 7: 11 ; which is not 180° + ∠ BOC = 180° +... Angles, ( ii ) angle BEC, ( iii ) Name all reflex! Be thought of as a fraction of a circle ∠AOB = 3x+4 ∠BOC Check! 97° + 83° = 180° ) r = 90° – x angles find! Red arc indicates angle BOF which is the radius 0 and b giving reasons b, c and d the!, by degree measure of each … ∠BOC = ∠COD = 38° find: reflex angle DOA = 180.! Also 4x Questions of Exe-24 a, Exe-24 b and Revision Exercise to skill. In the ratio 7: 5 angles of an isosceles triangle are equal lines cut by a transversal each... 0 + 68 0 = 248 0 the radius an angle is equal to supplement... ) straight line find angle AOB ∠AOC = 108° ∠AOB = ∠BOC = 97° + 83° 180°... ; AOC-is a straight line measures of two obtuse angles ( with their Types ) for ICSE Class-6 Concise Mathematics! And d in the ratio 7: 11 Justify your answer m∠AOB=4x−15, find.... ( x + 4 ) ° and ( 2x + 5 ) °, lines, rays...

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